If the expression , then one possible value of x could be:

If the expression

, then one possible value of x could be:
A . C 1
B . C 2
C . C 5
D . 1
E . 2

View Answer

Answer: A

Explanation:

Cross multiply and solve for x:

3 × 2x = ( 2 + x) × (x C 5)

6x = x 2 C 3x C 10

x 2 C 9x C 10 = 0

(x C 10) × (x + 1)

x = 10, x = C1