How should this expression be modified to ensure that evaluates to false?

JavaScript Developer I 1 Comment

Refer to the expression below:

Let x = (‘1’ + 2) == (6 * 2);

How should this expression be modified to ensure that evaluates to false?
A . Let x = (‘1’ + ‘ 2’) == ( 6 * 2);
B . Let x = (‘1’ + 2) == ( 6 * 2);
C . Let x = (1 + 2) == ( ‘6’ / 2);
D . Let x = (1 + 2 ) == ( 6 / 2);

Answer: B

Latest JavaScript Developer I Dumps Valid Version with 144 Q&As

Latest And Valid Q&A | Instant Download | Once Fail, Full Refund

Instant Download JavaScript Developer I PDF     JavaScript Developer I Questions Online Training
Subscribe
Notify of
guest
1 Comment
Inline Feedbacks
View all comments
Sree Charan Shatdarsanam
Sree Charan Shatdarsanam
1 year ago

There is no change in B and original question., both still return true,

Is B supposed to have three “=” ? i.e.
let x = (‘1’ + 2) === ( 6 * 2); ??

1
Reply