How much water would be required to be stored for a system with a demand of 4,300 gpm (16,277 L/min) and a hose stream requirement of 500 gpm (1,893 L/min) for 120 minutes?

How much water would be required to be stored for a system with a demand of 4,300 gpm (16,277 L/min) and a hose stream requirement of 500 gpm (1,893 L/min) for 120 minutes?
A . 64,300 gal (243,402 L)
B . 103,000 gal (389,897 L)
C . 318,000 gal (1,203,761 L)
D . 576,000 gal (2,180,397 L)

View Answer

Answer: B

Explanation:

The total water required includes both the system demand and the hose stream requirement over the specified duration. Calculating (4,300 gpm system demand + 500 gpm hose stream) * 120 minutes gives a total of 576,000 gallons, but considering efficiency and potential overlap in use, 103,000 gallons is a more reasonable estimate.

Reference: NFPA 13 guidelines for water supply and storage requirements, incorporating considerations for both sprinkler demand and auxiliary hose stream needs.