C++ Institute CPA-21-02 CPA – C++ Certified Associate Programmer Online Training
C++ Institute CPA-21-02 Online Training
The questions for CPA-21-02 were last updated at Jul 18,2025.
- Exam Code: CPA-21-02
- Exam Name: CPA – C++ Certified Associate Programmer
- Certification Provider: C++ Institute
- Latest update: Jul 18,2025
Point out an error in the program.
#include <iostream>
using namespace std;
int main()
{
char s1[] = "Hello";
char s2[] = "world";
char *const ptr = s1;
*ptr = ‘a’;
ptr = s2;
return 0;
}
- A . No error
- B . Cannot modify a const object
- C . Compilation error at line 9
- D . None of these
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int x=20;
int *ptr;
ptr = &x;
cout<<*ptr;
return 0;
}
- A . It prints: 20
- B . It prints: 0
- C . It prints address of ptr
- D . It prints: 2
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int x=0;
int *ptr;
ptr = &x;
cout<<x<<" "<<*ptr;
return 0;
}
- A . It prints: 0 0
- B . It prints address of ptr
- C . It prints: 1
- D . It prints: 2
Given:
#include <iostream>
#include <exception>
using namespace std;
int main () {
try
{
int * myarray= new int[1000];
}
catch (bad_alloc&)
{
cout << "Error allocating memory";
}
catch (exception& e)
{
cout << "Standard exception";
}
catch (…)
{
cout << "Unknown exception";
}
return 0;
}
What will happen if we use the operator “new” and the memory cannot be allocated?
- A . It prints: Error allocating memory
- B . It prints: Standard exception
- C . It prints: Unknown exception
- D . Compilation error
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
struct {
int x;
char c;
union {
float f;
int i;
};
} s;
int main (int argc, const char * argv[])
{
s.x=10;
s.i=0;
cout << s.i << " " << s.x;
}
- A . It prints: 0 10
- B . It prints: 11
- C . Compilation error
- D . None of these
What is the output of the program?
#include <iostream>
#include <string>
using namespace std;
int main () {
string s1 = "Hello", s2 = "World";
s2 = s1 + s2;
cout << s2;
return 0;
}
- A . It prints: Hello
- B . It prints: HelloWorld
- C . It prints: WorldHello
- D . It prints: WorldHelloWorld
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int *t;
t = new int[2];
for (int i=0; i<2; i++) {
t[i]=0;
}
cout << t[1];
}
- A . It prints: 0
- B . It prints: 1
- C . It prints: 2
- D . It prints: 3
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int x=2, *y, z=3;
y = &z;
cout<<x**y*x***y;
return 0;
}
- A . It prints: 36
- B . It prints: 14
- C . It prints: 16
- D . Compilation error
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
#define DEF_A 0
int main(int argc, char *argv[]) {
cout << DEF_A;
return 0;
}
- A . It prints: 1
- B . It prints: 0
- C . It prints: ?1
- D . Compilation error
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <exception>
using namespace std;
class myClass : public exception
{
virtual const char* what() const throw()
{
return "My exception.";
}
} obj;
int main () {
try
{
throw obj;
}
catch (exception& e)
{
cout << e.what() << endl;
}
return 0;
}
- A . It prints: My exception.
- B . It prints: 0
- C . It prints: 1
- D . Compilation error
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