What is the expected output of the following code?

What is the expected output of the following code?

x = True

y = False

z = False

if not x or y:

print(1)

elif not x or not y and z:

print(2)

elif not x or y or not y and x:

print(3)

else:

print(4)
A . 4
B. 3
C. 2
D. 1

View Answer

Answer: B

Explanation:

Topics: if elif else not and or operator precedence

Try it yourself:

x = True

y = False

z = False

# if not x or y:

# if (not True) or False:

# if False or False:

if False:

print(1)

# elif not x or not y and z:

# elif (not True) or (not False) and False:

# elif False or True and False:

# elif False or (True and False):

# elif False or False:

elif False:

print(2)

# elif not x or y or not y and x:

# elif (not True) or False or (not False) and True:

# elif False or False or True and True:

# elif False or False or (True and True):

# elif False or False or True:

# elif (False or False) or True:

# elif False or True:

elif True:

print(3) # 3

else:

print(4)

There are three operators at work here.

Of them the not operator has the highest precedence, followed by the and operator.

The or operator has the lowest precedence.